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What's the most general form of "not being a principal ideal due to singularity"?

A topic by tdgperson created Sep 24, 2020 Views: 266 Replies: 2
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Theorem 12.1.3 of Vakil's Foundations of Algebraic Geometry is that (x, z) is not a principal ideal in k[x,y,z] / (xy - z^2). The proof is to look at the ideal (x,y,z), which is a singular point. Therefore, the dimension of the Zariski tangent space at (x,y,z) is 3. However, if we quotient by (x,z), then the point (x,y,z) in k[x,y,z] / (xy-z^2, x,z) has dimension of the Zariski tangent space is 1. Quotienting by a principal ideal cannot make the dimension decrease by 2.

This theorem can probably be generalized to any situation a singular prime ideal contains a regular prime ideal. However, I'm having trouble writing down the exact formulation of the generalized theorem and proving it. What is the most general form of this theorem?

Moderator(+4)

I’m not sure what’s the math knowledge of the average user here, but wouldn’t it be more likely to get an answer if you ask that on a forum dedicated in math?

Maybe a place like the Math Stack Exchange would have more people with the experience and willingness to help you, although I’d suggest to read the rules for posting there as I’m not familiar to them.

I can make my calculator say 'Boobies'!