The numbers get pretty big, so while I idle, I might as well have some fun punching numbers!
By my count, the grid is 23x23, and assuming they're cubes, there's another 1 foot, making it 23x23x1. In total, a full grid punched out is 529 cubic feet of Earth matter, which is around 82.6 metric tons.
The center of Earth is 3,959 miles deep, or 20,903,520 (20.9 M) feet, 11.01 B cubic feet, or 1,726 gigatons of mass.
To reach the other end, it's as simple as doubling it to 41.8 M feet, 22.1 B cubic feet, or 3,453 gigatons of mass.
Now here comes the hard stuff, if you were to cut out a 23x23 area from the equator of Earth, you'd get 63.2 q cubic feet sliced from the center, or 9.9 Exatons (9.9 GigaGigaKilotons)
If you were to line up all the matter on Earth into a single line of 23x23, it would be 72.3 Q feet long and have a volume the same as Earth, 38.2 s cubic feet, as well as the same mass, 5.9 Zettatons (5.9 GigaGigaMegatons).
If the Sun itself was replaced with an Earth of the same volume, its surface gravity would go from an estimated 274 m/s^2 to a whopping 1,064 m/s^2, just under 4 times that of the Sun. The mass of the SolEarth, spread out in a 23x23 line, would extend to 93.5 S feet in length, or 3,011,049,728 Light Years. For reference, the Milky Way is only 52,850, and the Universe is 46.508 billion light years.
In order to reach one end of the Observable Universe to the other, using 23x23x1 foot tiles of Earth Matter, you will need 1.44 Octillion feet, or 59.83 solar masses / 119 Quettatons (119 GigaGigaGigaMegatons) of matter.