If you execute a Drunk Disguised as a Knight, do you take 2 DMG 'coz it was a Drunk or 9 DMG 'coz the Knight was corrupted?
6 damage.
My understanding is that, internally, the math goes like this:
5 dmg [standard penalty for innocent execution] + 4 dmg [corrupted knight penalty] + -3 dmg [drunk anti-penalty] = 6 net penalty
