Post by Schnurrfels in Gigabytes of RAM are now possible

Viewing post in Gigabytes of RAM are now possible

9 bytes: 24 RGB displays

address: 1 byte -> 256 possible addresses

9*256=2304=2.304KB

1GB = 1,000,000KB

1,000,000 / 2.304=434027.777...

meaning you need 434028 2.304KB-memory cells

(you need 10,416,672 RGB displays for 1GB)

I built a 16MT RAM (it lagged a ton). I used red and green for storing 1 byte and the display has 256 addresses.

So I want 1GiB, thats 2^30 bytes

2^30 / 256 = 4,194,304 RGB displays for 1GiB

There could also be an optimization where you use the blue channel across 2 addresses. So then in 2 physical addresses could be stored 3B.

So thats 384B in a single RGB display.
2^30 / 384 = 2,796,202 RGB displays for 1GiB