Ah, the question that's being asked by the game is "what position would these two dials be in if they were each incremented 1300 times," rather than "how many full rotations of each dial would add up to 1300?"
In this case, the answer would be
- Dial 1 (0-3): 1300 % 4 = 0
- Dial 2 (0-5): 1300 % 6 = 4