that phrase reads to me as; the sculpture is not blue and the square is not blue.
!((sq = bl) | (sc = bl))
=>
(Sq != bl) & (sc != bl)
You could say instead
There are no square or blue sculptures
!((sc = sq) | (sc = bl))
=>
(sc != sq) & (sc != bl)
See
https://math.stackexchange.com/questions/25091/translating-neither-nor-into-a-ma...
how is this not solve?