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(+1)

Astonishingly good gameplay loop, bravo.

My value record for one cell

That's gotta be pretty close to the maximum I think you could get (assuming we're not counting 800, surrounded by mines). If the top  left was a corner, you could get 10+7+7 in the top row, both 9s in the next row, then 8+8+11 in the bottom row, for a total of 69 in the middle. I can't  think of a way to top that without breaking some level-gen rule, and it would take incredible luck to get there. Getting three 8s would require giving up the 10, and that loses you more points overall.

I'm not 100% sure, but I think you can have only one 9 near a corner, because Romeo and Juliet always mirror each other's positions horizontally. I only noticed that like last week, after a VERY long time just thinking they were on the same row.

So I think the max would be a total of 67.

That's 8+8+8, 7+7, 9+11+9, either middle of 3rd row or 3rd from bottom row.

Or near a corner, 10+11+7, 9+7, 8+8+7. Either way, total of 67.

Ah, TIL how the lovers really work. That should help my speedrun attempts.

Bottom option won't work as the 7s are quadrant constrained and can't be side by side.