No likes 𝒮 ⊆ 𝕌 ∧ Card(𝒮) = ℵ₀ ∃U ∈ 𝒮 ∃x ∈ U \[R(x) ∧ x ∈ (1, 2)] ∀x ∈ (3, 4) ¬∃U ∈ 𝒮 (x ∈ U) X := {x ∈ ℚ | 1 < x < 2} Y := {x ∈ ℚ | 3 < x < 4} |X| = |Y| = ℵ₀ ∧ X ∩ Y = ∅ ℵ₀ ≠ All ∃𝒮 ⊆ 𝕌 \[Card(𝒮) = ℵ₀ ∧ ∀U ∈ Up his butt
